## General Chemistry

Knowing the units of the rate constant is important as it is used often for solving problems related to the rate laws.

# k Units of a Zero-Order Reaction

Zero-order indicates that the rate does not depend on the concentration, and therefore, the rate is equal to the concentration.

rate = k[A]0

[A]0 = 1, therefore,

rate = k

The units for the rate are mol/L, so it is the same as the rate constant:

k = mol/L s or M/s or M x s-1

# k Units of a First-Order Reaction

Let’s assume it is a first-order reaction in molecule A:

rate = k[A]

The units for the rate are mol/L. The rate constant is equal to:

$k\; = \;\frac{{{\rm{rate}}}}{{\left[ {\rm{A}} \right]}}$

And now, add the units for the rate and concentration:

$k\; = \;\frac{{{\rm{mol}}}}{{{\rm{L}}\; \times \;{\rm{s}}}}\; \div \;\frac{{{\rm{mol}}}}{{{\rm{L}}\;}}\; = \;\frac{{\cancel{{{\rm{mol}}}}}}{{\cancel{{\rm{L}}}\; \times \;{\rm{s}}}}\; \times \;\frac{{\cancel{{\rm{L}}}}}{{\cancel{{{\rm{mol}}}}}}\; = \;{{\rm{s}}^{{\rm{ – 1}}}}$

# k Units of a Second-Order Reaction

Let’s assume it is a second-order reaction in molecule A:

rate = k[A]2

$k\; = \;\frac{{{\rm{rate}}}}{{{{\left[ {\rm{A}} \right]}^2}}}$

And now, add the units for the rate and concentration:

$k\; = \;\frac{{{\rm{mol}}}}{{{\rm{L}}\; \times \;{\rm{s}}}}\; \div \;{\left( {\frac{{{\rm{mol}}}}{{{\rm{L}}\;}}} \right)^2}\; = \;\frac{{\cancel{{{\rm{mol}}}}}}{{\cancel{{\rm{L}}}\;{\rm{ \times }}\;{\rm{s}}}}\;{\rm{ \times }}\;\frac{{{{\rm{L}}^{\cancel{{\rm{2}}}}}}}{{{\rm{mol}}\cancel{{^{\rm{2}}}}}}\;\;{\rm{ = }}\;\frac{{\rm{L}}}{{{\rm{mol}}\; \times \;{\rm{s}}}}$

Alternatively, this can be written as M-1 · s-1

# A Shortcut to Determining the Units of Rate Constant

Notice how for each order, we determined the units of k by dividing the rate by molarity raised to the power of the reaction order:

$k\; = \;\frac{{{\rm{rate}}}}{{{{\left[ {\rm{A}} \right]}^n}}}$

where n is the reaction order

From this equation, a general formula for the units of k is obtained which is:

k units = M1-n · t-1

where n is the reaction order

For example, let’s say we want to determine the units of the rate constant for third-order reactions

n = 3, and therefore,

k units = M1-3 · t-1 = M-2 · t-1

If the time is seconds, then the units will be:

k units = M-2 · s-1

The following table summarizes the rate laws, half-lives, and k units for first-, second-, and zero-order reactions: Here is a 77-question, Multiple-Choice Quiz on Chemical Kinetics:

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